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4x^2-36.25x+81=0
a = 4; b = -36.25; c = +81;
Δ = b2-4ac
Δ = -36.252-4·4·81
Δ = 18.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36.25)-\sqrt{18.0625}}{2*4}=\frac{36.25-\sqrt{18.0625}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36.25)+\sqrt{18.0625}}{2*4}=\frac{36.25+\sqrt{18.0625}}{8} $
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